If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+3x-42^2=0
We add all the numbers together, and all the variables
2x^2+3x-1764=0
a = 2; b = 3; c = -1764;
Δ = b2-4ac
Δ = 32-4·2·(-1764)
Δ = 14121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14121}=\sqrt{9*1569}=\sqrt{9}*\sqrt{1569}=3\sqrt{1569}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{1569}}{2*2}=\frac{-3-3\sqrt{1569}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{1569}}{2*2}=\frac{-3+3\sqrt{1569}}{4} $
| 12x=-5-7x | | (2x+3)^2=16 | | −24−18p=38p2418p38p | | 4-4n=20 | | 9/4+1/7t=5 | | -8/3=-4k/3 | | x^2+x(x+3)=42^2 | | 12x=-5-7 | | -8/3=-4/3k | | x^2+x(x+3)=42 | | 3x+8+32=5x | | 6+y-1=7 | | 7/a=9 | | |3y-2|+4=10 | | 3x^2+16x=-16 | | 2(n−3)=4n+12n34n1 | | |6+x|=16 | | n^2+3n-7=0 | | (2/3)+y-(1/9)=(7/9) | | p2=0.81 | | 5q+2(-8+3q)=1-q | | −x^2+11x=28 | | −x2+11x=28 | | 2x-4=5(-x+2) | | 52=3x+13 | | 5x^-39x-54=0 | | 6=9/k | | 2*(x+8)^2=40 | | 22x=7+4x | | 13x-2(x+4)-8x=1 | | 6=9k | | -4(5x-2)+6=-15 |